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Physics help. How do you determine...formula?
An 85 kg skydiver jumps from a height of 550 m. If he deploys his parachute at a height of 350 m, what is his speed immediately before releasing his chute? (Assume no air resistance).
Answer:
The acceleration of the gravity should be given in order to solve this.
I assume it is g=10 m/s2 as it usually appears to be.
Newton's 2nd law:
F = m a (=) a = F/m => a= w/m => a = m g/ m => a = g = 10 m/s2
so s= 1/2 a t^2 => t^2 = 2s / a => t^2 =2 (550 - 350) / 10
=>t^2 = 2 200 / 10 = 40 => t= 20/root10 = 20root10/ 10 s
U = a t (=) U = 10 20root10/ 10 => U = 20root10 m/s























































